The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took the customers in the sample to check out was 4.9 minutes with a sample standard deviation of 0.5 minutes. Conduct a test to determine whether or not the mean waiting time of all customers is significantly more than 5 minutes.
Use a significance level of α = 0.01.
Here we have to test that
n = 100
Sample mean =
Sample standard deviation = s = 0.5
Here population standard deviation is not known so we will use here t test.
Test statistic:
t = -2
Test statistic = -2
Degrees of freedom = n - 1 = 99
alpha = 0.01
P value from excel using command:
=T.DIST.RT(2,99)
= 0.0241 (Round to 4 decimal)
P value = 0.0241
Here P value = 0.0241 > alpha = 0.01
So we fail to reject null hypothesis H0.
Conclusion: There is not sufficient evidence to conclude that the mean waiting time of all customers is significantly more than 5 minutes.
Get Answers For Free
Most questions answered within 1 hours.