Solution:
Given ,
= 3.6 ..Population SD
E = 0.05 Margin of error
c = 95% = 0.95 ...confidence level
Find sample size required.
c = 0.95
= 1- c = 1- 0.95 = 0.05
/2 = 0.025
Using Z table ,
= 1.96
Now, sample size (n) is given by,
= {(1.96* 3.6)/ 0.05}2
= 19914.8544
=19915 ..(round to the next whole number)
New sample size = 19915
Old sample size = 35
19915 - 35 = 19880
Additional 19880 students that should be surveyed.
What would be the degrees of freedom for a sample size of 48?
degrees of freedom = n - 1 = 48 - 1 = 47
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