An instructor of a biology class believes the average final exam score for his biology class was more than 75.
Suppose a sample of 25 was taken and the sample mean he observed was 78.48 and a standard deviation of 5 points. What is the value of the test statistic? Report your answer to 2 decimal places.
(hint: to determine which test statistic to calculate, you must think about what methods should be used. Either one-sample t-methods, one-sample z-methods or two-sample t-methods.
Solution :
=
75
=78.48
s = 5
n = 25
This is the right tailed test .
The null and alternative hypothesis is ,
H0 : =
75
Ha :
> 75
Test statistic = t
= (
-
) / s /
n
= (78.48 - 75 ) / 5 /
25
= 3.480
Test statistic = t = 3.480
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