If
Upper X overbar equals 96 comma Upper S equals 5 comma and n equals 16X=96, S = 5, and n = 16,
and assuming that the population is normally distributed, construct a 90% confidence interval estimate of the population mean,
muμ.
(Type an integer or decimal with two decimal places to the right of the decimal point as needed.)
A.93.81
less than or equals Upper X overbar less than or equals≤ X≤
98.19 found using CONFIDENCE.T(0.1,5,16)
B.93.94
less than or equals Upper X overbar less than or equals≤ X≤
98.06 found using CONFIDENCE.NORM(0.1,5,16)
C.95.84
less than or equals Upper X overbar less than or equals≤ X≤
96.16 found using CONFIDENCE.T(0.9,5,16)
D.93.73
less than or equals Upper X overbar less than or equals≤ X≤
98.27 found using CONFIDENCE.T(0.1,5,15
Solution :
degrees of freedom = n - 1 = 16 - 1 = 15
t/2,df = t0.05,15 = 1.753
Margin of error = E = t/2,df * (s /n)
= 1.753 * ( 5 / 16)
Margin of error = E = 2.19
The 90% confidence interval estimate of the population mean is,
- E + E
96 - 2.19 96 + 2.19
( 93.81 98.19 )
correct option is = A
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