he safety director of a large steel mill took samples at random from company records of minor work-related accidents and classified them according to the time the accident took place.
Number of | Number of | |||||||
Time | Accidents | Time | Accidents | |||||
8 up to 9 a.m. | 10 | 1 up to 2 p.m. | 6 | |||||
9 up to 10 a.m. | 6 | 2 up to 3 p.m. | 8 | |||||
10 up to 11 a.m. | 6 | 3 up to 4 p.m. | 7 | |||||
11 up to 12 p.m. | 16 | 4 up to 5 p.m. | 20 | |||||
Using the goodness-of-fit test and the 0.01 level of significance, determine whether the accidents are evenly distributed throughout the day.
H0: The accidents are evenly distributed
throughout the day.
H1: The accidents are not evenly distributed
throughout the day.
a) State the decision rule, using the 0.01 significance level.
b) Compute the value of chi-square.
c)What is your decision regarding H0?
A)The significance level for a given hypothesis test is a value for
which a P-value less than or equal to is considered statistically
significant. If the p value is 0.01 is considered significant or
insignificant for confidence interval of 0.99.
B)
observed frequencies of accidents (fo)=10,6,6,16,6,8,7,20
Total of accidents are: 10+6+6+19+6+8+7+20=79
Average = 79/8
expected frequencies (fe)= 79/8,79/8,79/8,/79/8,79/8,79/8,79/8,79/8
H0: Accidents are evenly distributed throughout the day
H1: Accidents are not evenly distributed throughout the day
chi-square test -statistic =sum(fo-fe)^2/fe = 20.09
Critical value = chi-inv(0.01,7)= 18.475
C)
Since the test statistic does fall inside the rejection region, we
do reject H0.
Using a 0.01 level of significance there is sufficient evidence to
conclude that
the accidents are not evenly distributed throughout the day.
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