Question

You have a pair of dice where one is “normal” with values of 1, 2, 3, 4, 5, and 6 on the faces, but the other has 3 faces with 0 (zero) and 3 faces with value 6. What is the probability distribution for the sum of the dice when you roll them?

Answer 1

below is probability distribution for the sum of the dice(S) when you roll them :

P(S=1)=P(1 on normal and 0 on other die) =(1/6)*(3/6)=1/12

P(S=2)=P(2 on normal and 0 on other die) =(1/6)*(3/6)=1/12

P(S=3)=P(3 on normal and 0 on other die) =(1/6)*(3/6)=1/12

P(S=4)=P(4 on normal and 0 on other die) =(1/6)*(3/6)=1/12

P(S=5)=P(5 on normal and 0 on other die) =(1/6)*(3/6)=1/12

P(S=6)=P(6 on normal and 0 on other die) =(1/6)*(3/6)=1/12

P(S=7)=P(1 on normal and 6 on other die) =(1/6)*(3/6)=1/12

P(S=8)=P(2 on normal and 6 on other die) =(1/6)*(3/6)=1/12

P(S=9)=P(3 on normal and 6 on other die) =(1/6)*(3/6)=1/12

P(S=10)=P(4 on normal and 6 on other die) =(1/6)*(3/6)=1/12

P(S=11)=P(5 on normal and 6 on other die) =(1/6)*(3/6)=1/12

P(S=12)=P(6 on normal and 6 on other die) =(1/6)*(3/6)=1/12