The widths of platinum samples manufactured at a factory are
normally distributed, with a mean of 1.1 cm and a standard
deviation of 0.1 cm. Find the z-scores that correspond to each of
the following widths. Round your answers to the nearest hundredth,
if necessary.
(a) 1.6 cm
z =
(b) 0.2 cm
z =
Solution :
Given that ,
mean = = 1.1
standard deviation = = 0.1
(a ) P(x < 1.6 ) = P[ ( x - ) / < ( 1.6 - 1.1 ) / 0.1 ]
= P( z < 5 )
The z - scores = 5.00
( b )
P( x < 0.2) = P[( x - ) / < ( 0.2 - 1.1 ) / 0.1]
= P ( z < -9 )
The z - score = -9.00
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