Question

A sample of 114 patients were given a drug to lower cholesterol. A 95% confidence interval for the mean reduction in cholesterol (in mmol/L) was (0.95, 1.06).

What was the sample mean reduction? (Round the final answer to two decimal places.)

The sample mean reduction was ______mmol/L.

Answer #1

High Cholesterol: A group of eight individuals with high
cholesterol levels were given a new drug that was designed to lower
cholesterol levels. Cholesterol levels, in milligrams per
deciliter, were measured before and after treatment for each
individual, with the following results: Individual Before After 1
253 202 2 237 213 3 282 184 4 276 205 5 246 179 6 258 209 7 293 181
8 276 187 Send data to Excel Part: 0 / 20 of 2 Parts...

The accompanying summary data on total cholesterol level
(mmol/l) was obtained from a sample of Asian postmenopausal women
who were vegans and another sample of such women who were
omnivores.
Diet
Sample Size
Sample Mean
Sample SD
Vegan
89
5.20
1.08
Omnivore
97
5.65
1.10
Calculate a 99% CI for the difference between population mean
total cholesterol level for vegans and population mean total
cholesterol level for omnivores. (Use μVegan −
μOmnivore. Round your answers to three decimal
places.)
,...

Use the sample data and confidence level given below to complete
parts (a) through (d).
A drug is used to help prevent blood clots in certain patients.
In clinical trials, among 4994 patients treated with the drug,
180 developed the adverse reaction of nausea. Construct a 95%
confidence interval for the proportion of adverse reactions.
a) Find the best point estimate of the population
proportion p.
(Round to three decimal places as needed.)
b) Identify the value of the margin...

In a clinical trial of Lipitor, a common drug used to lower
cholesterol, 863 patients were given a treatment of 10-mg
Atorvastatin tablets. Among them, 19 patients experienced flu
symptoms and 844 patients did not.
a) Estimate the probability that a patient taking the drug will
experience flu symptoms.
b) Is this unusual for a patient taking the drug to experience
flu symptoms? Explain.
c) If you know that the probability of flu symptoms for a person
not receiving any...

Use the sample data and confidence level given below to complete
parts (a) through (d).
A drug is used to help prevent blood clots in certain patients.
In clinical trials, among
4248
patients treated with the drug,
101
developed the adverse reaction of nausea. Construct a
95% confidence interval for the proportion of adverse
reactions.
a) Find the best point estimate of the population proportion
p.
(Round to three decimal places as needed.)
b) Identify the value of the margin...

Construct a 95% confidence interval to estimate the population
mean when x=122 and s =28 for the sample sizes below.
a) n=30 b) n=70 c) n=90
a) The 95% confidence interval for the population mean when
n=30 is from a lower limit of to an upper limit of. (Round to two
decimal places as needed.)
b) The 95% confidence interval for the population mean when
n=70 is from a lower limit of to an upper limit of . (Round to...

Use the sample data and confidence level given below to
complete parts (a) through (d).
A drug is used to help prevent blood clots in certain
patients. In clinical trials, among 4856 patients treated with
the drug, 144 developed the adverse reaction of nausea. Construct
a 95% confidence interval for the proportion of adverse
reactions.
a) Find the best point estimate of the population
proportion p.
(Round to three decimal places as
needed.)
b) Identify the value of the margin...

Use the given degree of confidence and sample data to
construct a confidence interval for the population mean
µ. Assume that the population has a normal
distribution.
A laboratory tested twelve chicken eggs and found that the mean
amount of cholesterol was 239 milligrams with s = 13.3 milligrams.
Construct a 95 percent confidence interval for the true mean
cholesterol content of all such eggs.
Group of answer choices
(230.4, 247.6)
(230.5, 247.5)
(230.6, 247.4)
(232.1, 245.9)

Construct the confidence interval for the population mean μ.
c=0.95, x= 9.5,σ=0.8,and n=44
A 95% confidence interval form μ is(_,_) (Round to two decimal
places as needed.)

In a study to assess the effectiveness of garlic for lowering
cholesterol, 50 adults were treated with garlic tablets.
Cholesterol levels were measured before and after treatment. The
changes in their LDL cholesterol (in mg/dL) have a mean of 8 and a
standard deviation of 4.
(a) Construct a 95% interval estimate of the mean change in LDL
cholesterol after the garlic tablet treatment. (Round the lower
bound and upper bound of the confidence interval to two decimal
places) Include...

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