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A medical researcher wanted to estimate the proportion of all births in the United States that...

A medical researcher wanted to estimate the proportion of all births in the United States that were by caesarian section. A random sample of 200 births showed that 48 were by caesarian section. Create a confidence interval at 90% confidence for the proportion of all US births that are by caesarian section

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Answer #1

given data are:-

sample size(n) = 200

sample proportion () = 48/200 = 0.24

z critical value for 90% confidence level, both tailed test be:-

the 90% confidence interval of the the proportion of all US births that are by caesarian section is:-

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