Question

A medical researcher wanted to estimate the proportion of all births in the United States that...

A medical researcher wanted to estimate the proportion of all births in the United States that were by caesarian section. A random sample of 200 births showed that 48 were by caesarian section. Create a confidence interval at 90% confidence for the proportion of all US births that are by caesarian section

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

given data are:-

sample size(n) = 200

sample proportion () = 48/200 = 0.24

z critical value for 90% confidence level, both tailed test be:-

the 90% confidence interval of the the proportion of all US births that are by caesarian section is:-

***in case of doubt, comment below. And if u liked the solution, please like.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A researcher wanted to estimate the true proportion of smokers in a certain city (?). He...
A researcher wanted to estimate the true proportion of smokers in a certain city (?). He selected a random sample of size ? = 50 people and found 15 smokers in the sample. a) Find a point estimate for (?). b) Find a 95% confidence interval for (?). c) If we use the sample proportion (?̅) to estimate (?), calculate the margin of error using the confidence level 0.95
Q. A researcher wanted to estimate the true proportion of smokers in a certain city (?)....
Q. A researcher wanted to estimate the true proportion of smokers in a certain city (?). He selected a random sample of size ? = 50 people and found 15 smokers in the sample. a) Find a point estimate for (?). b) Find a 95% confidence interval for (?). c) If we use the sample proportion (?̅) to estimate (?), calculate the margin of error using the confidence level 0.95.
The countries of Europe report that 48% of the labor force is female. The United Nations...
The countries of Europe report that 48% of the labor force is female. The United Nations wonders if the percentage of females in the labor force is the same in the United States. Representatives from the United States Department of Labor plan to check a random sample of over 10,000 employment records on file to estimate a percentage of females in the United States labor force. The representatives from the department of labor want to estimate the percentage of females...
A community college wants to estimate the proportion of students who are active in student government....
A community college wants to estimate the proportion of students who are active in student government. A random sample of 224 students showed 56 were active in student government. Create a confidence interval at 90% confidence for the proportion of all students in that college who were active in student government.
Use the one-proportion z-interval procedure to find the required confidence interval. A researcher wishes to estimate...
Use the one-proportion z-interval procedure to find the required confidence interval. A researcher wishes to estimate the proportion of adults in the city of Darby who are vegetarian. In a random sample of 1323 adults from this city, the proportion that are vegetarian is 0.068. Find a 90% confidence interval for the proportion of all adults in the city of Darby that are vegetarians.
1. A tourist agency on the border of Canada and the United States wants to know...
1. A tourist agency on the border of Canada and the United States wants to know if a majority of the proportion of visitors going to Niagara Falls are from the United States. A random survey was conducted on 150 visitors at Niagara Falls. Of those surveyed, 90 were from the United States. a.If you were to create a confidence interval for the true proportion of visitors to Niagara Falls that are from the United States, which test statistic would...
a researcher wishes to estimate the proportion of adults in the city of Darby who are...
a researcher wishes to estimate the proportion of adults in the city of Darby who are vegetarian. in a random sample of 1729 adults from the city's proportion that are vegetarian is 0.083. find a 95% confidence interval for the proportion of all adults in the city of Darby that are vegetarians.
Surgical complications: A medical researcher wants to construct a 98% confidence interval for the proportion of...
Surgical complications: A medical researcher wants to construct a 98% confidence interval for the proportion of knee replacement surgeries that result in complications. ) Estimate the sample size needed if no estimate of p is available. A sample of __operations is needed to obtain a 98%confidence interval with a margin of error of 0.08 when no estimate of p is available.
A marketing firm wanted to estimate the proportion of protected homes. it chose a random sample...
A marketing firm wanted to estimate the proportion of protected homes. it chose a random sample of 200 homes. and found that 53 had home security systems, Estimate the true proportion of homes with security systems with a 99% confidence
Surgical complications: A medical researcher wants to construct a 98% confidence interval for the proportion of...
Surgical complications: A medical researcher wants to construct a 98% confidence interval for the proportion of knee replacement surgeries that result in complications. (a) An article in a medical journal suggested that approximately 20% of such operations result in complications. Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.08? A sample of__?/ operations is needed to obtain a 98% confidence interval with a margin of error of 0.08...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT