Question

In a certain school district, it was observed that 25% of the students in the element schools were classified as only children (no siblings). However, in the special program for talented and gifted children, 114 out of 386 students are only children. The school district administrators want to know if the proportion of only children in the special program is significantly different from the proportion for the school district. Test at the α=0.05 level of significance.

What is the hypothesized population proportion for this test?
p=
(Report answer as a decimal accurate to 2 decimal places. Do not report using the percent symbol.)

Based on the statement of this problem, how many tails would this hypothesis test have?

• one-tailed test
• two-tailed test

Choose the correct pair of hypotheses for this situation:

(A)	(B)	(C)	H0:p=0.25H0:p=0.25 Ha:p<0.25Ha:p<0.25	H0:p=0.25H0:p=0.25 Ha:p≠0.25Ha:p≠0.25	H0:p=0.25H0:p=0.25 Ha:p>0.25Ha:p>0.25				(D)	(E)	(F)	H0:p=0.295H0:p=0.295 Ha:p<0.295Ha:p<0.295	H0:p=0.295H0:p=0.295 Ha:p≠0.295Ha:p≠0.295	H0:p=0.295H0:p=0.295 Ha:p>0.295Ha:p>0.295

Using the normal approximation for the binomial distribution (without the continuity correction), was is the test statistic for this sample based on the sample proportion?
z=
(Report answer as a decimal accurate to 3 decimal places.)

You are now ready to calculate the P-value for this sample.
P-value =
(Report answer as a decimal accurate to 4 decimal places.)

This P-value (and test statistic) leads to a decision to...

• reject the null
• accept the null
• fail to reject the null
• reject the alternative

As such, the final conclusion is that...

• There is sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program.
• There is not sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program.
• The sample data support the assertion that there is a different proportion of only children in the G&T program.
• There is not sufficient sample evidence to support the assertion that there is a different proportion of only children in the G&T program.

PLEASE SHOW WORK. THANK YOU!!

Answer 1

Solution :

This is the two tailed test .

The null and alternative hypothesis is

Option b ) is correct.

H₀ : p = 0.25

H_a : p 0.25

n = 386

x = 114

= x / n = 114 / 386 =0.295

P₀ = 0.25

1 - P₀ = 1 - 0.25 = 0.75

Test statistic = z

= - P₀ / [P_{0 *} (1 - P₀ ) / n]

=0.295 - 0.25 / [0.25 * 0.75 / 386 ]

= 2.057

Test statistic = z = 2.057

P-value = 0.0397

= 0.05

P-value <

0.0397 < 005

Reject the null hypothesis .

There is sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program.