Question

The manufacturer of a fertilizer guarantees that, with the aid of the fertilizer, 80% of planted seeds will germinate. Suppose the manufacturer is correct. If 9 seeds planted with the fertilizer are randomly selected, what is the probability that more than 6 of them germinate? Carry your intermediate computations to at least four decimal places, and round your answer to two decimal places. (If necessary, consult a list of formulas.)

Answer 1

Let , X be the number of seeds to be germinated.

Here , X has binomial distribution with parameter n=9 and p=0.80

Therefore , the probability mass function of X is ,

; x=0,1,2,............,n

= 0 ; otherwise

Now , we want to find the probability that more than 6 of them germinate.

Therefore , the probability that more than 6 of them germinate is 0.74.