Two genes’ expression values follow a bivariate normal distribution. Let X and Y denote their expression values respectively. Also assume that X has mean 9 and variance 3; Y has mean 10 and variance 5; and the covariance between X and Y is 2. In a trial, 50 independent measurements of the expression values of the two genes are collected, and denoted as 1 1 ( , ) X Y , …, 50 50 ( , ) X Y . We wish to find the probability P X Y ( 0.5 ) , that is, the probability that the sample mean for the second gene exceeds the sample mean of the first gene by more than 0.5. Conduct a Monte Carlo simulation to approximate this probability, providing a 95% confidence interval for your estimation. Submit your R script for the Monte Carlo simulation, and a brief summary of the actual simulation results.
NOTE:: I HOPE THIS ANSWER IS HELPFULL TO YOU......***PLEASE SUPPORT ME WITH YOUR RATING....THANK YOU....
Get Answers For Free
Most questions answered within 1 hours.