A statistician working for the National Basketball Association supplies the television announcers with interesting statistics. At a certain point in the season, he discovered that of the 375 games where a team was winning the game at the end of the third quarter, 300 of those games were won by the team that was already winning. Please show all steps.
A 90% confidence interval for the proportion of winning the game, when winning after the third quarter, in the whole season, is given by:
sample success x = | 300 | |
sample size n= | 375 | |
sample proportion p̂ =x/n= | 0.8000 | |
std error se= √(p*(1-p)/n) = | 0.0207 | |
for 90 % CI value of z= | 1.645 | |
margin of error E=z*std error = | 0.034 | |
lower bound=p̂ -E = | 0.7660 | |
Upper bound=p̂ +E = | 0.8340 | |
from above 90% confidence interval for population proportion =(0.766,0.834) |
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