Let X represent the number that occurs when a 6-sided red die is tossed and Y the number that occurs when a 6-sided green die is tossed. Find the variance of the random variable 6X-Y.
The value of 6X - Y is computed for different combinations of X, Y as:
X = 1 | X = 2 | X = 3 | X = 4 | X = 5 | X = 6 | |
Y = 1 | 5 | 11 | 17 | 23 | 29 | 35 |
Y = 2 | 4 | 10 | 16 | 22 | 28 | 34 |
Y = 3 | 3 | 9 | 15 | 21 | 27 | 33 |
Y = 4 | 2 | 8 | 14 | 20 | 26 | 32 |
Y = 5 | 1 | 7 | 13 | 19 | 25 | 31 |
Y = 6 | 0 | 6 | 12 | 18 | 24 | 30 |
The expected value and second moment of 6X - Y are first computed here as:
E(6X - Y) = 6E(X) - E(Y)
E(X) = E(Y) = (1 + 2 + 3 + 4 + 5 + 6) / 6 = 3.5
Therefore, E(6X - Y) = 6E(X) - E(Y) = 6*3.5 - 3.5 = 5*3.5 = 17.5
Now the second moment is computed here as:
E( (6X - Y)2) = (52 + 42 + .... + 312 + 302) / 36 = 14910/36 = 414.17
Therefore Var(6X - Y) = E( (6X - Y)2) - [E(6X - Y)]2 = 414.17 - 17.52 = 107.9167
Therefore 107.9167 is the required variance here.
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