Question

Climate change part II. We considered the differences between the temperature reading in Jan of 1968...

Climate change part II. We considered the differences between the temperature reading in Jan of 1968 and 2008 at 51 locations in the continental US in exercise 4.9 The mean and standard deviation of the reported differences are 1.1 degrees and 4.9 degrees Caculate a 95% CI for the average difference between the temperature measurements between 1968 and 2008.

Interpret that this interval in context

does the CI provide convincing evidence that the temperature was different in 2008 Interpret this CI in context

Does the CI provide convincing evidence that the temperature was different in 2008 than in 1968 in the continental US? Explain.

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

sample size n = 51 > 30. So, we will consider z distribution instead of t distribution

mean and standard deviation for difference are 1.1 and 4.9

z critical for 95% interval level is 1.96

No,  CI does not provide convincing evidence that the temperature was different in 2008 because 0 is included in confidence interval.

We are 95% confidence that the true differences between the temperature reading in Jan of 1968 and 2008 were between -0.195 degrees to 2.395 degrees.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Let's consider a small scale example, comparing how temperatures have changed in the US from 1968...
Let's consider a small scale example, comparing how temperatures have changed in the US from 1968 to 2008. The daily high temperature reading on January 1 was collected in 1968 and 2008 for 51 randomly selected locations in the continental US. Then the difference between the two readings (temperature in 2008 - temperature in 1968) was calculated for each of the 51 different locations. The average of these 51 values was 1.1 degrees with a standard deviation of 4.9 degrees....
Is there strong evidence of global warming? Let's consider a small scale example, comparing how temperatures...
Is there strong evidence of global warming? Let's consider a small scale example, comparing how temperatures have changed in the US from 1968 to 2008. The daily high temperature reading on January 1 was collected in 1968 and 2008 for 51 randomly selected locations in the continental US. Then the difference between the two readings (temperature in 2008 - temperature in 1968) was calculated for each of the 51 different locations. The average of these 51 values was 1.1 degrees...
We considered the differences between the reading and writing scores of a random sample of 200...
We considered the differences between the reading and writing scores of a random sample of 200 students who took the High School and Beyond Survey in Exercise 7.20. The mean and standard deviation of the differences are  and 8.887 points. (a) Calculate a 95% confidence interval for the average difference between the reading and writing scores of all students. (b) Interpret this interval in context. (c) Does the confidence interval provide convincing evidence that there is a real difference in the...
5.22 High School and beyond, Part II: We considered the differences between the reading and writing...
5.22 High School and beyond, Part II: We considered the differences between the reading and writing scores of a random sample of 200 students who took the High School and Beyond Survey in Exercise 5.21. The mean and standard deviation of the differences are x̄read-write = -0.545 and 8.887 points respectively. (a) Calculate a 95% confidence interval for the average difference between the reading and writing scores of all students. lower bound: points (please round to two decimal places) upper...
5.22 High School and beyond, Part II: We considered the differences between the reading and writing...
5.22 High School and beyond, Part II: We considered the differences between the reading and writing scores of a random sample of 200 students who took the High School and Beyond Survey in Exercise 5.21. The mean and standard deviation of the differences are x̄read-write = -0.545 and 8.887 points respectively. (a) Calculate a 95% confidence interval for the average difference between the reading and writing scores of all students. lower bound: points (please round to two decimal places) upper...
ON GRAPHING CALCULATOR PLEASE 7. A survey of 50 people was conducted to compare their self-reported...
ON GRAPHING CALCULATOR PLEASE 7. A survey of 50 people was conducted to compare their self-reported height to their actual height. The difference between reported height and actual height was calculated. You're testing the claim that the mean difference is greater than 1.3. From the sample, the mean difference was 1.6, with a standard deviation of 0.44. Calculate the test statistic, rounded to two decimal places 9. We considered the differences between the temperature readings in January 1 of 1968...
Part 1: z-Procedures In this part, we will use z-procedures. z-procedures are both confidence intervals and...
Part 1: z-Procedures In this part, we will use z-procedures. z-procedures are both confidence intervals and hypothesis tests that use a Normal distribution. They are called z-procedures because they rely on a z-test statistic and/or a z-critical value. So far, we can use z-procedures for a population mean knowing the population standard deviation. In Part 1, you will use the data file TempSample00-18. (THIS IS DATA) YEAR,Month,High Temperature 2000,Jan,45 2000,Jan,48 2001,Jan,49 2003,Jan,62 2003,Jan,53 2004,Jan,42 2004,Jan,47 2005,Jan,40 2005,Jan,47 2006,Jan,48 2006,Jan,47 2007,Jan,51...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT