Question

The average amount of a beverage in randomly selected 16-ounce beverage can is 16.18 ounces with a standard deviation of 0.4 ounces. If a random sample of sixty-five 16-ounce beverage cans are selected, what is the probability that the mean of this sample is less than 16.1 ounces of beverage? Answer: (keep 4 decimal places)  

Answer 1

Solution :

Given that ,

mean = = 16.18

standard deviation = = 0.4

n = 65

= = 16.18

= / n = 0.4 / 65 = 0.0496

P( < 16.1) = P(( - ) / < (16.1 - 16.18) / 0.0496)

= P(z < -1.61)

Using z table

= 0.0537