Question

The average amount of a beverage in randomly selected 16-ounce beverage can is 15.96 ounces with a standard deviation of 0.5 ounces. If a random sample of sixty-five 16-ounce beverage cans are selected, what is the probability that the mean of this sample is less than 16.05 ounces of beverage? Answer: (keep 4 decimal places)

Answer 1

Solution :

Given that ,

mean = = 15.96

standard deviation = = 0.5

= / n = 0.5 / 65 = 0.0620

P( < 16.05) = P(( - ) / < (16.05 - 15.96) / 0.0620)

= P(z < 1.45)

= 0.9265

Probability = 0.9265