Determine if there is sufficient evidence to conclude the average amount of births is over 5000 in the United States and territories at the 0.05 level of significance. N=52
Summary Table for Live births |
|
Mean |
6,785 |
Median |
4,462 |
Standard Deviation |
8119 |
Minimum |
519 |
Maximum |
46,661 |
Given that, sample size = 52
sample mean = 6785 and standard deviation = 8119
The null and alternative hypotheses are,
H0 : μ = 5000
Ha : μ > 5000
Test statistic is,
=> Test statistic = z = 1.59
p-value = P(Z > 1.59) = 1 - P(Z < 1.59) = 1 - 0.9441 = 0.0559
=> p-value = 0.0559
Since, p-value = 0.0559 is greater than 0.05 level of significance, we fail to reject the null hypothesis.
Conclusion : There is not sufficient evidence to conclude the average amount of births is over 5000 in the United States and territories at the 0.05 level of significance.
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