Suppose that a sample has been drawn from a normal population to conduct the hypothesis test
H0:σ2=33
H1:σ2>33
Assume that you know that the sample variance is s2=63, the sample size is n=24, and take α=0.09. Draw the sampling distribution, and use it to determine each of the following:
A. The test statistic is:
B. The p-value is
C. Your decision for the hypothesis test:
A. Do Not Reject H1H1.
B. Do Not Reject H0H0.
C. Reject H0H0.
D. Reject H1H1.
Given that, sample size (n) = 24 and
sample variance (s2) = 63
The null and alternative hypotheses are,
A) Test statistic is,
=> Test statistic = 43.909
B) Using Excel we find, the p-value
Degrees of freedom = 24 - 1 = 23
Excel Command : =CHIDIST(43.909, 23) = 0.0054
p-value = 0.0054
c) Since, p-value is less than α=0.09, we reject the null hypothesis.
Therefore, your decision for the hypothesis test : Reject H0
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