Suppose that the heights of students are normally distributed with mean 67 inches and standard deviation 3 inches. (a) What is the probability that a randomly chosen student is at least 69 inches tall? (b) What is the probability that the mean height of a random sample of 5 students is at least 69 inches? (c) What is the probability that the mean height of a random sample of 20 students is at least 69 inches?
Given,
= 67 , = 3
We convert this to standard normal as
P( X < x) = P( Z < x - / )
a)
P( X >= 69) = P( Z >= 69 - 67 / 3)
= P( Z >= 0.6667)
= 1 - p( Z < 0.6667)
= 1 - 0.7475
= 0.2525
b)
The central limit theorem is
P( < x) = P( Z < x - / / sqrt(n) )
So, for n = 5
P( >= 69) = P( Z >= 69 - 67 / 3 / sqrt(5) )
= P( Z >= 1.4907)
= 1 - P( Z < 1.4907)
= 1 - 0.9320
= 0.0680
c)
for n = 20
P( >= 69) = P( Z >= 69 - 67 / 3 / sqrt(20) )
= P (Z >= 2.9814)
= 1 - P( Z < 2.9814)
= 1 - 0.9986
= 0.0014
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