Answer:
Given,
p^ = x/n = 200/400 = 0.5
Here we use z test
Ho : advising group decided to investigate that believing it was not too large
Ha : advising group decided to investigate that believing it was too large
test statistic z = (p^ - p)/sqrt(p(1-p)/n)
substitute values
= (0.5 - 0.6)/sqrt(0.6(1-0.6)/400)
= - 4.08
P value = 0.000045 [since from z table]
= 0.0000
Here p value < alpha,so we reject Ho.
So there is sufficient evidence to support the claim.
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