Suppose you play a game in which you charge someone $10 to roll two dice. If they get doubles (either two ones, two twos, two threes, etc.), then you pay them $50 (for a net profit of $ -40 to you). If they don’t get doubles, then you keep their $10. a. Write out a probability distribution for X, the net profit to you. b. What is the expected value of the game from your point of view?
X : Net Profit to you
X : -$40 ; if they get doubles;
X : $10 ; it they do not get a double.
Event space (highlighted doubles)
Dice 1 | Dice 2 |
1 | 1 |
1 | 2 |
1 | 3 |
1 | 4 |
1 | 5 |
1 | 6 |
2 | 1 |
2 | 2 |
2 | 3 |
2 | 4 |
2 | 5 |
2 | 6 |
3 | 1 |
3 | 2 |
3 | 3 |
3 | 4 |
3 | 5 |
3 | 6 |
4 | 1 |
4 | 2 |
4 | 3 |
4 | 4 |
4 | 5 |
4 | 6 |
5 | 1 |
5 | 2 |
5 | 3 |
5 | 4 |
5 | 5 |
5 | 6 |
6 | 1 |
6 | 2 |
6 | 3 |
6 | 4 |
6 | 5 |
6 | 6 |
Number possible events when two dice are rolled : (6x6) = 36
Number of possible events of getting a double when two dice are rolled = 6
Probability of getting a double when two dice are rolled = 6/36 = 1/6
Probability of not getting a double = 1-Probability of getting a double = 1 - 1/6 = 5/6
Probability distribution of X:
X | P(X) |
-40 | 1/6 |
10 | 5/6 |
Expected value of the game from your point of view : E(X)
Expected value of the game from your point of view = 10/6 = $1.6667
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