For each of the following probabilities, shape- the area under the standard normal curve corresponding to the probability. Then find the requested probability.
a.) P(z<-0.23)
b.) P(0.17<z<2.1)
c.) P(-0.3< z < 1.35)
d.) P(z > -1.73)
e.) P(-0.17 < z < 1.35)
f.) P(z > 0.67)
solution
(A)P(z <-0.23 )
Using z table
=0.4090
probability=0.4090
(B)
P( 0.17< Z < 2.1)
= P(Z < 2.1) - P(Z <0.17 )
Using z table,
=0.9821 - 0.5675
=0.4146
probability=0.4146
(C)
( -0.3< Z < 1.35)
= P(Z < 1.35) - P(Z -0.3 )
Using z table,
=0.9115 - 0.3821
=0.5294
probability=0.5294
(D)
P(z > -1.73) =1 - P(z <-1.73 )
Using z table,
= 1 -0.0418
= 0.9582
(e) P(-0.17 < z < 1.35)
P(Z < 1.35) - P(Z <-0.17 )
Using z table,
=0.9115 - 0.4325
=0.4790
probability=0.4790
(f)
P(z > 0.67) =1 - P(z <0.67 )
Using z table,
= 1 -0.7486
= 0.2514
Get Answers For Free
Most questions answered within 1 hours.