Solution :
Given that ,
mean = = 854
standard deviation = = 12
n = 30
= 854
= / n= 12 / 30=2.1909
P( 844< <858 ) = P[( 844-854) /2.1909 < ( - ) / < ( 858-854) /2.1909 )]
= P(-4 < Z < 1.83)
= P(Z < 1.83) - P(Z < -4)
Using z table
=0.9664-0
=0.9664
probability=0.9664
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