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A hospital director is told that 78% of the emergency room visitors are insured. The director...

A hospital director is told that 78% of the emergency room visitors are insured. The director wants to test the claim that the percentage of insured patients is below the expected percentage. A sample of 200 patients found that 150 were insured. Find the value of the test statistic. Round your answer to two decimal places.

Math   Statistics-And-Probability   
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Answer #1

= 150/200 = 0.75

The test statistic z = ( - P)/sqrt(P(1 - P)/n)

                              = (0.75 - 0.78)/sqrt(0.75 * (1 - 0.75)/200)

                              = -0.98

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