The number of cars arriving at a gas station can be modelled by Poisson distribution with the average rate of 5 cars per 10 minutes. a. The probability that one car will arrive to a gas station in a 5 -minute interval is _________ b. The probability that at least one car will arrive to the gas station in a 10 - minute interval is ______
X ~ Poi ( )
Where = 5 cars per 10 min
Poisson probability distribution is
P(X) = e- * X / X!
a)
For 5 min, = 5 * 5 / 10 = 2.5
P(X = 1) = e-2.5 * 2.5 = 0.2052
b)
For 10 minutes, = 5
P(X >= 1) = 1 - P(X = 0)
= 1 - e-5
= 0.9933
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