Assume the amount of inventory of raw material 1 can be approximated to a normal distribution which a mean 47lb and standard deviation 14lb. What is the probability that a random sample of 100 inventory readings show a sample mean greater than 44lb?
Solution :
Given that,
mean = = 47
standard deviation = = 14
n = 10
= 47
= / n = 14 100 = 1.4
P ( > 44 )
= 1 - P ( < 44 )
= 1 - P ( - /) < (44- 47 /1.4 )
= 1 - P( z < - 3 / 1.4 )
= 1 - P ( z < - 2.14 )
Using z table
= 1 - 0.0162
= 0.9838
Probability = 0.9838
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