This is a binomial distribution question with
n = 2000
p = 0.81
q = 1 - p = 0.18999999999999995
This binomial distribution can be approximated as Normal distribution since
np > 5 and nq > 5
Since we know that
P(x > 1600.0)=?
The z-score at x = 1600.0 is,
z = -1.14
This implies that
P(x > 1600.0) = P(z > -1.14) = 1 - 0.1271431505627983
P(x > 1600.0) = {0.8729}
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