The monthly revenue at a christian rock band has records to indicate that the mean monthly revenue is $2,400 and standard deviation is $600. A random sample of 81 months was selected. Find the approximate probability that the average revenue for the sample is less than $2,300.
Solution :
Given that ,
= $2400
=
/
n = 600 /
81 = 66.67
P( < 2.300) = P((
-
) /
< (2300 - 2400) / 600)
= P(z < - 1.50)
Using z table
= 0.0668
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