About 73% of all female heart transplant patients will survive for at least 3 years. Seventy female heart transplant patients are randomly selected. What is the probability that the sample proportion surviving for at least 3 years will be less than 66%? Assume the sampling distribution of sample proportions is a normal distribution. The mean of the sample proportion is equal to the population proportion and the standard deviation is equal to StartRoot StartFraction pq Over n EndFraction EndRoot .
The probability that the sample proportion surviving for at least 3 years will be less than 66% is
Solution
Given that,
p = 0.73
1 - p = 1 - 0.73 = 0.27
n = 70
= p = 0.73
= [p ( 1 - p ) / n] = [(0.73 * 0.27) / 70 ] = 0.0531
P( < 0.66)
= P[( - ) / < (0.66 - 0.73) / 0.0531]
= P(z < -1.32)
Using z table,
= 0.0934
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