Question

What is the probability of not rolling any 6’s in four rolls of a balanced die?

Answer 1

The total number of possible outcomes when 6's are rolled in four rolls of a balanced dice: 6⁴ = 1296

We need to find the probability of not rolling any sixes.

P(not rolling any 6's)

= P(no six on first roll) * P(no six on the second roll) * P(no six on third roll) * P(no six on fourth roll)

= 5/6 * 5/6 * 5/6 * 5/6

= 625/1296

=0.4822530864

Hence the required probability is 48.2253%

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