Question

give information about the proportion of a sample that agrees with a certain statement. Use StatKey or other technology to estimate the standard error from a bootstrap distribution generated from the sample. Then use the standard error to give a 95% confidence interval for the proportion of the population to agree with the statement. StatKey tip: Use “CI for Single Proportion” and then “Edit Data” to enter the sample information.

3.82 In a random sample of 250 people, 180 agree.

recognize that pHat=180/250 and n=250.

Please complete this problem using Rstudio. Show all work, including rstudio code.

thank you.

Answer 1

The StatKey output is:

The 95% confidence interval for the proportion of the population to agree with the statement is between 0.6601 and 0.7719.

Observed
0.716	p (as decimal)
179/250	p (as fraction)
179.	X
250	n
0.0316	std. error
0.6601	confidence interval 95.% lower
0.7719	confidence interval 95.% upper
0.0559	margin of error