Question

Identify the critical t. An independent random sample is selected from an approximately normal population with...

Identify the critical t. An independent random sample is selected from an approximately normal population with unknown standard deviation find the degrees of freedom and the critical t value (t*) for the given sample size and confidence level.

n=6,CL=90%

N=21, CL=98%

n=29, CL= 95%

n=12,CL=99%

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
you are calculating a confidence interval for the population mean. Find the critical value t* from...
you are calculating a confidence interval for the population mean. Find the critical value t* from the t-Distribution Critical Values table for each of the following situations A 95% confidence interval based on n = 12 observations. A 99% confidence interval from a sample of two observations. A 90% confidence interval from a sample of size 1001. 2. Suppose you conduct a hypothesis test for the following hypotheses from a sample of n = 25 observations, and you calculate a...
A simple random sample of size n is drawn from a population that is normally distributed....
A simple random sample of size n is drawn from a population that is normally distributed. The sample​ mean, is found to be 109, and the sample standard​ deviation, s, is found to be 10. ​(a) Construct a 98% confidence interval about m μ if the sample​ size, n, is 21. ​(b) Construct a 98% confidence interval about mu μ if the sample​ size, n, is 26. ​(c) Construct a 99% confidence interval about mu μ if the sample​ size,...
Refer to slide 11 in the PowerPoint deck 13. Look at the examples below and determine...
Refer to slide 11 in the PowerPoint deck 13. Look at the examples below and determine whether the conditions for the estimation of the mean are met, and if so, whether it is appropriate to look up the critical values from the normal (z) or Student’s t (t) distributions, and look up the appropriate critical values. If the conditions are not met, indicate that none of these is applicable: Confidence level Sample size N Population standard deviation Distribution shape Z...
The following information was obtained from independent random samples. The Degrees of Freedom have be calculated...
The following information was obtained from independent random samples. The Degrees of Freedom have be calculated to be 19. The Standard Deviations are Unknown. Small Sample Size: Use t-value Sample 1 Sample 2 Sample Mean 45 42 Sample Variance 85 90 Sample Standard Deviation Sample Size 10 12 Standard Error Confidence Coefficient 0.95 Level of Significance Degrees of Freedom 19 t-value Margin of Error Point Estimate of Difference 3 Lower Limit Upper Limit The point estimate for the difference between...
Suppose you have selected a random sample of ?=14 measurements from a normal distribution. Compare the...
Suppose you have selected a random sample of ?=14 measurements from a normal distribution. Compare the standard normal ? values with the corresponding ? values if you were forming the following confidence intervals. (a)    90% confidence interval z= t= (b)    95% confidence interval z=   t= (c)    98% confidence interval ?= t= 2) A confidence interval for a population mean has length 20. a) Determine the margin of error. b) If the sample mean is 58.6, obtain the confidence interval. Confidence interval: ( ,...
Based on a random sample of 21 observations selected from a normal population, the sample standard...
Based on a random sample of 21 observations selected from a normal population, the sample standard deviation is s = 7.2. We test Ho : σ2 = 30 vs. Ha : σ2 > 30 at the 0.05 level of significance. Find the rejection region and the observed value of the test statistic. (a) The rejection region is χ2 > 32.6705 with 21 degrees of freedom and the observed value of the test statistic is 34.56 (b) The rejection region is...
A random sample of n = 11 observations was selected from a normal population. The sample...
A random sample of n = 11 observations was selected from a normal population. The sample mean and variance were x = 3.93 and s2 = 0.3216. Find a 90% confidence interval for the population variance σ2. (Round your answers to three decimal places.)
Find the following critical t-scores used in an 88% confidence interval for a population mean when...
Find the following critical t-scores used in an 88% confidence interval for a population mean when the population’s standard deviation (σσ) is unknown. Give each answer to at least three decimal places. The t-critical value for an 88% confidence interval with sample size 38 is: The t-critical value for an 88% confidence interval with sample size 48 is: The t-critical value for an 88% confidence interval with sample size 64 is: The t-critical value for an 88% confidence interval with...
A simple random sample of size n is drawn from a population that is normally distributed....
A simple random sample of size n is drawn from a population that is normally distributed. The sample​ mean, x overbarx​, is found to be 112​, and the sample standard​ deviation, s, is found to be 10. ​ (a) Construct aa 98​% confidence interval about muμ if the sample​ size, n, is 26. ​ (b) Construct aa 98​% confidence interval about muμ if the sample​ size, n, is 12. ​(c) Construct aa 90​% confidence interval about muμ if the sample​...
Find a confidence interval for μ assuming that each sample is from a normal population. (Round...
Find a confidence interval for μ assuming that each sample is from a normal population. (Round the value of t to 3 decimal places and your final answers to 2 decimal places.) (a) x⎯⎯ = 28, s = 5, n = 8, 90 percent confidence. The 90% confidence interval is to (b) x⎯⎯ = 50, s = 6, n = 15, 99 percent confidence. The 99% confidence interval is to (c) x⎯⎯ = 111, s = 11, n = 29,...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT