Question

The students who took Mrs. Johnson's math quiz scored a mean of 51 with a variance...

The students who took Mrs. Johnson's math quiz scored a mean of 51 with a variance of 46. Since the scores were low, Mrs. Johnson decided to curve the scores. If Peter had an original score of 32 and a curved score of 68, and Rachel had an original score of 86 and a curved score of 95, what is the sum of the mean and standard deviation of the new score distribution? Round to the nearest thousandth.

Math   Statistics-And-Probability   
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Answer #1

Plug this value in equation 1), we get

68 = - 2.8014*3.391165

= 68 +9.5 = 77.5

So the mean of the new score distribution = 77.5

and the standard deviation of the new score distribution = 3.391

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