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In a random sample of six mobile devices, the mean repair cost was $60.00 and the...

In a random sample of six mobile devices, the mean repair cost was $60.00 and the standard deviation was $12.50. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 99% confidence interval for the population mean. Interpret the results.
The 99% confidence interval for the population μ is (_, _)

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Answer #1

Margin of error = 4.032*12.5/

= 20.576

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