Question

In a random sample of six mobile devices, the mean
repair cost was $60.00 and the standard deviation was $12.50.
Assume the population is normally distributed and use a
t-distribution to find the margin of error and construct a 99%
confidence interval for the population mean. Interpret the
results.

The 99% confidence interval for the population μ is (_, _)

Answer #1

Margin of error = 4.032*12.5/

= 20.576

**Please upvote if you have liked my answer, would be of
great help. Thank you.**

In a random sample of six mobile devices, the mean repair cost
was $75.00 and the standard deviation was $13.0013.00. Assume the
population is normally distributed and use a t-distribution to
find the margin of error and construct a 95% confidence interval
for the population mean. Interpret the results.
The 95% confidence interval for the population mean μ is

In a random sample of four mobile devices, the mean repair cost
was $65.00 and the standard deviation was $13.50. Assume the
population is normally distributed and use a t-distribution to
find the margin of error and construct a 99% confidence interval
for the population mean. Interpret the results.

In a random sample of four mobile devices, the mean repair cost
was $85.00 and the standard deviation was $12.00. Assume the
population is normally distributed and use a t-distribution to
find the margin of error and construct a 95% confidence interval
for the population mean. Interpret the results. The 95% confidence
interval for the population mean mu is ( ,). (Round to two
decimal places as needed.) The margin of error is $ nothing.
(Round to two decimal places...

1) Use the given confidence interval to find the margin of error
and the sample mean. (12.8,19.8)
2) In a random sample of four microwave ovens, the mean repair
cost was $60.00 and the standard deviation was $12.00. Assume the
population is normally distributed and use a t-distribution to
construct a 99% confidence interval for the population mean ?.
What is the margin of error of ? Interpret the results.

In a random sample of 13 microwave ovens, the mean repair cost
was $70.00 and the standard deviation was $15.40.
Using the standard normal distribution with the appropriate
calculations for a standard deviation that is known, assume the
population is normally distributed, find the margin of error and
construct a 98% confidence interval for the population mean. A
98% confidence interval using the t-distribution was
(58.5,81.5).
Find the margin of error of the population mean.
Find the confidence interval of...

In a random sample of 22 people, the mean commute time to work
was 32.1 minutes and the standard deviation was 7.3 minutes. Assume
the population is normally distributed and use a t-distribution to
construct a 99% confidence interval for the population mean μ.
What is the margin of error of μ? Interpret the results.

In a random sample of 28 people, the mean commute time to work
was 33.6 minutes and the standard deviation was 7.1 minutes. Assume
the population is normally distributed and use a t-distribution to
construct a 99% confidence interval for the population mean μ.
What is the margin of error of μ? Interpret the results.

In a random sample of six people, the mean driving distance to
work was 18.3 miles and the standard deviation was 4.3 miles.
Assume the population is normally distributed and use the
t-distribution to find the margin of error and construct a 90%
confidence interval for the population mean mu. Interpret the
results.
Identify the margin of error.

In a random sample of 29 people, the mean commute time to work
was 30.1 minutes and the standard deviation was 7.2 minutes. Assume
the population is normally distributed and use a t-distribution to
construct a 80% confidence interval for the population mean μ?
What is the margin of error of μ? Interpret the results.

In a random sample of 25 people, the mean commute time to work
was 30.6 minutes and the standard deviation was 7.2 minutes.
Assume the population is normally distributed and use a
t-distribution to construct a 95% confidence interval for the
population mean μ.
What is the margin of error of μ? Interpret the results.
1. The confidence interval for the population mean μ is
(_,_)
2. The margin of error of μ is __
3. Interpret the results.
A.It...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 15 minutes ago

asked 32 minutes ago

asked 32 minutes ago

asked 57 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago