Question
A livestock company reports that the mean weight of a group of young steers is 1164...
A livestock company reports that the mean weight of a group of young steers is 1164 pounds with a standard deviation of 90 pounds. Based on the model N(1164,90) for the weights of steers, what percent of steers weigh
a) over 1100 pounds? b) under 900 pounds? c) between 1150 and 1200 pounds?
Homework Answers
Answer #1
Mean, 
= 1164 pounds
SD, 
= 90 pounds
We know, Z = 
(a) Percentage of steers who weigh over 1100 pounds
= P(X > 1100)*100%
= P{Z > (1100 - 1164)/90}*100%
= P(Z > -0.711)*100%
= 76.14%
(b) Percentage of steers who weigh under 900 pounds
= P(X < 900)*100%
= P{Z < (900 - 1164)/90}*100%
= P(Z < -2.933)*100%
= 0.17%
(c) Percentage of steers who weigh between 1150 and 1200 pounds
= P(1150 < X < 1200)*100
= P{(1150 - 1164)/90 < Z < (1200 - 1164)/90}*100
= P(-0.156 < Z < 0.4)*100%
= 0.1744*100 = 17.44%
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