An advertising agency wishes to estimate,
within
95% confidence and to
within
two percentage po
ints, the
proportion
of all adults who recognize its
client’s logo. Knowing that two years ago the proportion was 19%, then the
estimated minimum
sample size
needed is
(a)
2401
(b)
1042
(c)
1479
(d)
966
(e)
1566
Solution :
Given that,
= 0.19
1 - = 1 - -0.19 = 0.81
Margin of error = E = 0.02
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
Sample size = ( Z/2 / E)2 * * (1 - )
= (1.96 / 0.02)2 * 0.19 * 0.81
= 1478.05
Sample size = n = 1479
Option C) Is correct .
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