Question

A random sample of 100observations from a population with standard deviation 23.99 yielded a sample mean of 94.1

1. Given that the null hypothesis is *μ*=90μ=90 and the
alternative hypothesis is *μ*>90μ>90 using
*α*=.05α=.05, find the following:

(a) Test statistic ==

(b) *P* - value:

(c) The conclusion for this test is:

**A.** There is insufficient evidence to reject the
null hypothesis

**B.** Reject the null hypothesis

**C.** None of the above

2. Given that the null hypothesis is *μ*=90μ=90 and the
alternative hypothesis is *μ*≠90μ≠90 using
*α*=.05α=.05, find the following:

(a) Test statistic ==

(b) *P* - value:

(c) The conclusion for this test is:

**A.** Reject the null hypothesis

**B.** There is insufficient evidence to reject the
null hypothesis

**C.** None of the above

Answer #1

A random sample of 100100 observations from a population with
standard deviation 10.7610.76 yielded a sample mean of
91.891.8.
1. Given that the null hypothesis is μ=90μ=90 and the
alternative hypothesis is μ>90μ>90 using α=.05α=.05, find the
following:
(a) Test statistic ==
(b) P - value:
(c) The conclusion for this test is:
A. There is insufficient evidence to reject the
null hypothesis
B. Reject the null hypothesis
C. None of the above
2. Given that the null hypothesis is μ=90μ=90...

A random sample of 36 values is drawn from a mound-shaped and
symmetric distribution. The sample mean is 14 and the sample
standard deviation is 2. Use a level of significance of 0.05 to
conduct a two-tailed test of the claim that the population mean is
13.5.
(a) Is it appropriate to use a Student's t
distribution? Explain.
Yes, because the x distribution is mound-shaped and
symmetric and σ is unknown.No, the x distribution
is skewed left. No, the x
distribution...

You may need to use the appropriate appendix table or technology
to answer this question.
Consider the following hypothesis test.
H0: μ = 15
Ha: μ ≠ 15
A sample of 50 provided a sample mean of 14.11. The population
standard deviation is 3.
(a)
Find the value of the test statistic. (Round your answer to two
decimal places.)
(b)
Find the p-value. (Round your answer to four decimal
places.)
p-value =
(c)
At
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state your conclusion....

The age distribution of the Canadian population and the age
distribution of a random sample of 455 residents in the Indian
community of a village are shown below.
Age
(years)
Percent of
Canadian Population
Observed
Number
in the Village
Under 5
7.2%
45
5 to 14
13.6%
74
15 to 64
67.1%
286
65 and older
12.1%
50
Use a 5% level of significance to test the claim that the age
distribution of the general Canadian population fits the age...

A sample mean, sample standard deviation, and sample size are
given. Use the one-mean t-test to perform the required hypothesis
test about the mean, μ, of the population from which the sample was
drawn. Use the critical-value approach.
, , n = 11, H0: μ = 18.7, Ha: μ ≠ 18.7, α =
0.05
Group of answer choices
Test statistic: t = 1.03. Critical values: t = ±2.201. Do not
reject H0. There is not sufficient evidence to conclude
that...

Consider the following hypothesis test.
H0: p = 0.30
Ha: p ≠ 0.30
A sample of 500 provided a sample proportion
p = 0.275.
(a)
Compute the value of the test statistic. (Round your answer to
two decimal places.)
(b)
What is the p-value? (Round your answer to four decimal
places.)
p-value =
(c)
At
α = 0.05,
what is your conclusion?
Do not reject H0. There is sufficient
evidence to conclude that p ≠ 0.30.Do not reject
H0. There...

The age distribution of the Canadian population and the age
distribution of a random sample of 455 residents in the Indian
community of a village are shown below.
Age (years)
Percent of Canadian Population
Observed Number
in the Village
Under 5
7.2%
51
5 to 14
13.6%
69
15 to 64
67.1%
292
65 and older
12.1%
43
Use a 5% level of significance to test the claim that the age
distribution of the general Canadian population fits the age...

The following table shows ceremonial ranking and type of pottery
sherd for a random sample of 434 sherds at an archaeological
location.
Ceremonial
Ranking
Cooking Jar
Sherds
Decorated
Jar Sherds (Noncooking)
Row
Total
A
87
48
135
B
90
55
145
C
74
80
154
Column
Total
251
183
434
Use a chi-square test to determine if ceremonial ranking and
pottery type are independent at the 0.05 level of significance.
(a) What is the level of significance?
(b) Find the...

Test the claim about the population mean,μ, at the given level
of significance using the given sample statistics
Claim: μ not equal 7000; alpha=0.09; sigma (SD) =374.
Samplestatistics: x =7300, n=34
1. identify the null and alternative hypotheses
2. what is the standardized test statistic
3. Determine the critical value (round to two decimal places as
needed)
4. Determine the outcome and conclusion of the test (choose from
choices below)
a. Fail to reject H0 - not enough evidence to...

A random sample of 51 adult coyotes in a region of northern
Minnesota showed the average age to be x = 2.01 years,
with sample standard deviation s = 0.76 years. However, it
is thought that the overall population mean age of coyotes is
μ = 1.75. Do the sample data indicate that coyotes in this
region of northern Minnesota tend to live longer than the average
of 1.75 years? Use α = 0.01.
(a) What is the level of...

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