Question

A random sample of 100observations from a population with standard deviation 23.99 yielded a sample mean of 94.1

1. Given that the null hypothesis is *μ*=90μ=90 and the
alternative hypothesis is *μ*>90μ>90 using
*α*=.05α=.05, find the following:

(a) Test statistic ==

(b) *P* - value:

(c) The conclusion for this test is:

**A.** There is insufficient evidence to reject the
null hypothesis

**B.** Reject the null hypothesis

**C.** None of the above

2. Given that the null hypothesis is *μ*=90μ=90 and the
alternative hypothesis is *μ*≠90μ≠90 using
*α*=.05α=.05, find the following:

(a) Test statistic ==

(b) *P* - value:

(c) The conclusion for this test is:

**A.** Reject the null hypothesis

**B.** There is insufficient evidence to reject the
null hypothesis

**C.** None of the above

Answer #1

A random sample of 100100 observations from a population with
standard deviation 10.7610.76 yielded a sample mean of
91.891.8.
1. Given that the null hypothesis is μ=90μ=90 and the
alternative hypothesis is μ>90μ>90 using α=.05α=.05, find the
following:
(a) Test statistic ==
(b) P - value:
(c) The conclusion for this test is:
A. There is insufficient evidence to reject the
null hypothesis
B. Reject the null hypothesis
C. None of the above
2. Given that the null hypothesis is μ=90μ=90...

From a random sample from normal population, we observed sample
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A sample of 25 provided a sample mean x = 14
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(b) Use the t distribution table to compute a range for
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What are the null and alternative hypotheses? Choose the
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A.H0: μ≠24
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(a) Is it appropriate to use a Student's t
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conduct a two-tailed test of the claim that the population mean is
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(a) Is it appropriate to use a Student's t
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Yes, because the x distribution is mound-shaped and
symmetric and σ is unknown.No, the x distribution
is skewed left. No, the x
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(a) Is it appropriate to use a Student's t
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Yes, because the x distribution is mound-shaped and
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A random sample of 36 values is drawn from a mound-shaped and
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