Question

It is believed that the Satisfaction Level of an employee is uniformly distributed between 0.1 and 1.0.

a. What is the probability that an employee will have a satisfaction level of exactly .75?

b. What is the probability that an employee will have a satisfaction level greater than .90?

c. What is the probability that an employee will have a satisfaction level of less than .40? d. What is the probability that an employee will have a satisfaction level between .60 and .90?

Answer 1

Solution :

Given that,

a = 0.1

b = 1.0

a) P(x = c) = (c - a) / (b - a)

P(x = 0.75) = (0.75 - 0.1) / (1.0 - 0.1)

P(x = 0.75) = 0.72

b) P(x > c) = (b - c) / (b - a)

P(x > 0.90) = (1.0 - 0.90) / (1.0 - 0.1)

P(x > 0.90) = 0.11

c) P(x < c) = (c - a) / (b - a)

P(x < 0.40) = (0.40 - 0.1) / (1.0 - 0.1)

P(x < 0.40) = 0.33

d) P(c < x < d) = (d - c) / (b - a)

P(0.60 < x < 0.90) = (0.90 - 0.60) / (1.0 - 0.1)

P(0.60 < x < 0.90) = 0.33