assume that test scores are normally distributed. A random sample of 25 SAT scores has a mean 1120 with a standard deviation 190. If (a,b) is the 95% confidence interval for the mean of all SAT scores constructed based on this sample, then, to the nearest whole number, a= b=
Solution :
Degrees of freedom = df = n - 1 = 24
At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
t /2,df = t0.025,24 = 2.064
Margin of error = E = t/2,df * (s /n)
= 2.064 * (190 / 25)
= 78
The 95% confidence interval estimate of the population mean is,
- E < < + E
1120 - 78 < < 1120 + 78
1042 < < 1198
(1042 , 1198)
a = 1042
b = 1198
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