he table provides summary statistics on highway fuel economy of cars manufactured in 2012 (from Exercise 5.32). Use these statistics to calculate a 98% confidence interval for the difference between average highway mileage of manual and automatic cars, and interpret this interval in the context of the data.
Hwy MPG, Automatic | Hwy MPG, Manual | |
---|---|---|
Mean | 22.92 | 27.88 |
SD | 5.29 | 5.01 |
n | 26 | 26 |
lower bound: mpg (please round to two decimal
places)
upper bound: mpg (please round to two decimal
places)
Interpret your confidence interval in the context of the
problem:
Does your confidence interval provide significant evidence for a
difference in the highway fuel efficiency of automatic versus
manual cars? Explain.
LicensePoints possible: 3
This is attempt 1 of 4.
For Manual : x̅1 = 27.88, s1 = 5.01, n1 = 26
For Automatic : x̅2 = 22.92, s2 = 5.29, n2 = 26
df = ((s1²/n1 + s2²/n2)²)/[(s1²/n1)²/(n1-1) + (s2²/n2)²/(n2-1) ] = 49.8529 = 50
98% Confidence interval for the difference :
At α = 0.02 and df = 50, two tailed critical value, t_c = T.INV.2T(0.02, 50) = 2.403
Lower Bound = (x̅1 - x̅2) - t_c*√(s1²/n1 +s2²/n2)
= (27.88 - 22.92) - 2.403*√(5.01²/26 + 5.29²/26) = 1.53
Upper Bound = (x̅1 - x̅2) + t_c*√(s1²/n1 +s2²/n2)
= (27.88 - 22.92) + 2.403*√(5.01²/26 + 5.29²/26) = 8.39
--
We can be 98% confident that the difference in average highway mileage of manual and automatic cars is contained within our confidence interval.
--
no, since 0 is not contained within our confidence interval.
Get Answers For Free
Most questions answered within 1 hours.