Suppose that 7 female and 6 male applicants have been successfully screened for 5 positions. If the 5 positions are filled at random from the 13 finalists, what is the probability of selecting no females?
solution:
the given information as follows;
number of male finalist = 6
number of female finalist = 7
total finalist = 13
number of ways of selecting 5 candidate out of total 13 =
we have to find the probability of selecting no females
so number of ways 5 male out of 6 male can be selected is =
so probability of selecting 5 if there are no female = 6 / 1287 = 0.0047
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