Question

y = 505.51x - 995806

r^{2} = 0.9964

Find and state the value of *r*^{2}, the
coefficient of determination, and r, the correlation coefficient.
Discuss your findings in a few sentences. Is r positive or
negative? Why? Is a line a good curve to fit to this data? Why or
why not? Is the linear relationship very strong, moderately strong,
weak, or nonexistent?

Choose a value of interest and use the line of best fit to make an estimate or prediction. Show calculation work.

Write a brief narrative of a paragraph or two. Summarize your findings and be sure to mention any aspect of the linear model project (topic, data, scatterplot, line, r, or estimate, etc.) that you found particularly important or interesting.

Answer #1

Given Linear equation is

**Y(hat)= 505.51*X-995806**

**R squared=0.9964**

**The value of coefficient of determination R squared =
0.9964. 0.9964** **indicates that the model explains
99.64% of the variability of the response data around its
mean.**

**Correlation Coefficient is square root of coefficient of
determination.**

**r= sqrt(0.9964)**

**r= 0.9982**

**r is POSITIVE .Because the slope of the equation is
POSITIVE.**

**Yes ,** line is a good curve to fit to this data
because of high R squared value.

The linear relationship very strong because r =0.9982 is close to 1.

Suppose X= 2000 Units

**Y(hat)= 505.51*X-995806**

Y(hat)= 505.51*420-995806

**Y(hat)= 15214 Units**

**For X=2000 Units the predicted Value= 15214
Units.**

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p-value
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5.8004
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0.7135
8.5154
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ln(Year)
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0.6156
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1.8821
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