A guard works between 5 p.m. and 12 midnight; he sleeps an average of 1 hour before 9 p.m. and 1.5 hours between 9 and 12. An inspector finds him asleep, what is the probability that this happens before 9 p.m.?
The guard works for a total of 7 hours.
P(Time between 5 and 9) = 4/7
P(Time between 9 and 12) = 3/7
P(sleep between 5 and 9 PM) = 1/4
P(Sleep between 9 and 12) = 1.5/3 = 1/2
We need to find the probability:
P(Time between 5 and 9/ Sleeping)
= P(Sleeping between 5 and 9) / P(Sleeping)
{Using Bayes theorem}
Hence the required probability is 40%.
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