Using the following table answer the questions:
NATIONALITY |
ADULTS |
CHILDREN |
TOT_SPEND |
DAYS |
BRITISH |
2 |
3 |
876 |
16 |
BRITISH |
2 |
2 |
275 |
4 |
BRITISH |
2 |
2 |
302 |
5 |
BRITISH |
1 |
3 |
423 |
11 |
BRITISH |
2 |
2 |
659 |
7 |
BRITISH |
2 |
1 |
358 |
10 |
FRENCH |
2 |
1 |
800 |
13 |
FRENCH |
2 |
2 |
923 |
14 |
FRENCH |
3 |
0 |
357 |
12 |
FRENCH |
1 |
3 |
271 |
5 |
FRENCH |
1 |
2 |
444 |
9 |
FRENCH |
2 |
3 |
415 |
6 |
FRENCH |
2 |
2 |
1245 |
15 |
GERMAN |
2 |
2 |
960 |
11 |
GERMAN |
1 |
3 |
642 |
10 |
GERMAN |
1 |
3 |
1531 |
15 |
GERMAN |
3 |
0 |
885 |
15 |
GERMAN |
2 |
2 |
1420 |
13 |
GERMAN |
2 |
3 |
1834 |
14 |
GERMAN |
3 |
0 |
597 |
9 |
ITALIAN |
2 |
3 |
436 |
5 |
ITALIAN |
2 |
1 |
594 |
11 |
ITALIAN |
2 |
1 |
292 |
4 |
ITALIAN |
2 |
2 |
650 |
8 |
ITALIAN |
2 |
2 |
349 |
3 |
ITALIAN |
2 |
2 |
453 |
2 |
ITALIAN |
2 |
3 |
609 |
6 |
Is mean spending per day per person affected by Nationality?
i. Select the appropriate test of hypothesis and state the null and alternative hypothesis
ii. Test the null hypothesis at 95% confidence level and state your conclusions.
The hypothesis being tested is:
H0: µ1 = µ2 = µ3 = µ4
Ha: At least one means is not equal
The output is:
Mean | n | Std. Dev | |||
482.2 | 6 | 236.93 | BRITISH | ||
636.4 | 7 | 359.84 | FRENCH | ||
1,124.1 | 7 | 474.59 | GERMAN | ||
483.3 | 7 | 137.62 | ITALIAN | ||
688.9 | 27 | 412.33 | Total | ||
ANOVA table | |||||
Source | SS | df | MS | F | p-value |
Treatment | 18,97,699.83 | 3 | 6,32,566.611 | 5.77 | .0043 |
Error | 25,22,652.83 | 23 | 1,09,680.558 | ||
Total | 44,20,352.67 | 26 |
The p-value from the output is 0.0043.
Since the p-value (0.0043) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that the mean spending per day per person is affected by Nationality.
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