The data show the time intervals after an eruption (to the next eruption) of a certain geyser. Find the regression equation, letting the first variable be the independent (x) variable. Find the best predicted time of the interval after an eruption given that the current eruption has a height of 97 feet. Use a significance level of 0.05.
Height (ft) | 116 | 157 | 154 | 122 | 137 | 100 | 102 | 110 |
Interval after (min) | 80 | 89 | 98 | 87 | 82 | 73 | 81 | 75 |
What is the regression equation?
y = ___ + ___x (Round to two decimal places as needed.)
What is the best predicted time for the interval after an eruption that is 97 feet high?
The best predicted interval time for an eruption that ism 97 feet high is ____ minutes.
(Round to one decimal place as needed.)
Using Excel we get, the regression equation is,
y = 45.59 + 0.30x
We want to predict y for x = 97 feet
y = 45.59 + (0.30 * 97)
=> y = 45.59 + 29.1
=> y = 74.69
=> y = 74.7
Therefore, the best predicted interval time for an eruption that ism 97 feet high is 74.7 minutes.
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