Question

A botanist wishes to estimate the typical number of seeds for a certain fruit. She samples 60 specimens and counts the number of seeds in each. Use her sample results (mean = 57.3, standard deviation = 11.5) to find the 95% confidence interval for the number of seeds for the species. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places.  

95% C.I. =

* Can you please print clear so I can understand it. Thank you so much.

Answer 1

Solution :

degrees of freedom = n - 1 = 60 - 1 = 59

t/2,df = 2.001

Margin of error = E = t/2,df * (s /n)

= 2.001 * ( 11.5 / 60)

Margin of error = E = 2.971

The 95% confidence interval estimate of the population mean is,

  ± E

57.3 ± 2.971

(54.329 , 60.271)