To improve turnover (employees leaving your organization), you implemented a new training program company-wide about a year ago. However, you're not sure that the training is equally effective in reducing turnover between your service department, sales departments, and warehouse. To test this, you retrieved a list of all current and former employees that have received the training and created a dataset also recording their department. Conduct a test of independence to investigate this.
Turnover | Department |
---|---|
Former Employee | Warehouse |
Current Employee | Service |
Current Employee | Sales |
Former Employee | Warehouse |
Current Employee | Sales |
Former Employee | Sales |
Current Employee | Sales |
Current Employee | Service |
Former Employee | Warehouse |
Current Employee | Sales |
Current Employee | Service |
Current Employee | Warehouse |
Current Employee | Service |
Current Employee | Warehouse |
Current Employee | Service |
Former Employee | Sales |
Former Employee | Sales |
Former Employee | Service |
The p-value for this chi-square was (Term 1 0.03did2.33did not0.332.2311.98) and the chi-square value was (Term 2 0.03did2.33did not0.332.2311.98.) This test (Term 3 0.03did2.33did not0.332.2311.98 achieve) statistical significance. The expected value for Former Employee/Service was (Term 4 0.03did2.33did not0.332.2311.98), while the observed value was (Term 5 0.03did2.33did not0.332.2311.98.)
Using SPSS:
The Chi square value is 2.231
Where p value is 0.328 that is greater the 0.05 It's means the test not statistically significant and we do not reject the null hypothesis.So there is no association between Turnover and Department.
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