Question

Determine the required **sample size** to estimate
a population proportion with a Confidence Level of 95% and E =
0.084.

Answer #1

Solution,

Given that,

= 1 - = 0.5

margin of error = E = 0.084

At 95% confidence level

= 1 - 95%

= 1 - 0.95 =0.05

/2
= 0.025

Z/2
= Z_{0.025} = 1.96

sample size = n = (Z_{ / 2} / E )^{2} *
* (1 -
)

= (1.96 / 0.084 )^{2} * 0.5 *0.5

= 136.11

sample size = n = 137

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