Calculate the following probabilities using the standard normal distribution. (Round your answers to four decimal places.)
(a)
P(0.0 ≤ Z ≤ 1.6)
(b)
P(−0.1 ≤ Z ≤ 0.0)
(c)
P(0.0 ≤ Z ≤ 1.49)
(d)
P(0.6 ≤ Z ≤ 1.51)
(e)
P(−2.05 ≤ Z ≤ −1.76)
(f)
P(−0.02 ≤ Z ≤ 3.54)
(g)
P(Z ≥ 2.60)
(h)
P(Z ≤ 1.66)
(i)
P(Z ≥ 6)
(j)
P(Z ≥ −8)
Solution :
(a)
P(0.0 ≤ Z ≤ 1.6) = P(z < 1.6) - P(z < 0) = 0.4452
(b)
P(−0.1 ≤ Z ≤ 0.0) = P(z < 0) - P(z < -1) = 0.3413
(c)
P(0.0 ≤ Z ≤ 1.49) = P(z < 1.49) - P(z < 0) = 0.4319
(d)
P(0.6 ≤ Z ≤ 1.51) = P(z < 1.51) - P(z < 0.60 = 0.2087
(e)
P(−2.05 ≤ Z ≤ −1.76) = P(z < -1.76) - P(z < -2.05) = 0.0190
(f)
P(−0.02 ≤ Z ≤ 3.54) = P(z < 3.54) - P(z < -0.02) = 0.5078
(g)
P(z > 2.60) = 1 -P(z < 2.60) = 0.0047
(h)
P(z < 1.66) = 0.9515
(i)
P(z > 6) = 1 - P(z < 6) = 1 - 1 = 0
(j)
P(z > -8) = 1 - P(z < -8) = 1 - 0 = 1
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